https://pastebin.com/L4p2dpk4
My code is there ^^
** if ((drug_potency_loss < 100 && drug_potency_loss > 0) && (target_effectiveness > 25 && target_effectiveness < 100)) {
cout << "Potency loss = " << drug_potency_loss / 100.00 << endl; // This will calculate the potency loss in decimal numbers instead of percentage numbers.
cout << "Target effectiveness = " << target_effectiveness << endl; // cout statement tells the user the target effectiveness.
cout << " " << endl; //creates a blank line.
cout << "Determining drug effectiveness: ..." << endl; // cout statement.
cout << "" << endl; // blank line.
}**
(Lines 22-28)
With this code, the user is supposed to enter -4 50
and then it will say error, try again
101 (error)
100 (error)
and then 4 (the code will work)
but the output from my code won't show.
However, whenever I type in 4 50 for the first time, the output shows. I put all of my code in a do-loop but for some reason, the output that is bolded will only appear whenever I type in the correct numbers.
I'm trying to make that specific part of the code show regardless of the attempts tried.
That's all I needed help fixing.
*AND YES THE CODE COMPILES AND THE LOOP WORKS*